Question

A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.096g of carbon and 0.144g of oxygen. calculate the percentage composition of the compound by weight​ .

Answer 1

Mass of the given sample compound = 0.24g

Mass of boron in the given sample compound = 0.096g

Mass of oxygen in the given sample compound = 0.144g

% composition of compound = % of boron and % of oxygen

Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100

= 40%

Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100

= 60%

Thank me

Answer 2

60%

Explanation:

mass of oxygen = 0.24

carbon= 0.096g

oxygen = 0.144g