A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.09g of boron and 0.144grams of oxygen. calculate the percentage composition of the compound by mass
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percentage of boron=mass of boron in compound/mass of compound ×100
=0.096g/0.24g ×100
=40 percent
percentage of oxygen =mass of oxygen in compound/ mass of ccompound10
= 0.144g/0.242410
=60 percent
=0.096g/0.24g ×100
=40 percent
percentage of oxygen =mass of oxygen in compound/ mass of ccompound10
= 0.144g/0.242410
=60 percent
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