Question

A 0.24g sample of compound of oxygen and boron was found by analysis that contain 0.096g of boron and 0.144g of oxygen. calculate the percentage compound sition of the compound by mass ​

Answer 1

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$\huge\bold\purple{Answer:-}$

⭐ Percentage of boron in the sample= 0.096/0.24 × 100 = 40%

and,

⭐ Percentage of oxygen in the sample= 0.144/0.24 × 100= 60%

⏩Hence, the sample of compound contains 40% boron and 60% oxygen by mass.

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Answer 2

Answer: 60% of oxygen and 40% of boron

given: (1).compound of oxygen+boron-0.24g...(2).boron-0.096g...(3).oxygen-0.144g

solution:A sample compound of oxygen and boron= 0.24g

in which boron=0.096g/0.24g multiplied by 100=40%

whereas oxygen=0.144g/0.24g multiplied by 100=60%

hence,the composition of compound by it's weight is boron=40% and oxygen= 60%

hope it'ill help..