Question

A 0.24g sample of compound of oxygen and boron was founded by analysis to contain 0.096 of boron and 0.144g of oxygen. calculate the percentage composition of the compound by weight.

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Answer 1

Answer:

60 % of Boron

40 % of oxygen

Explanation:

mass of compound =0.24 g

mass of boron=0.096 g

mass of oxygen=0.144 g

% of Boron= mass of boron/mass of compound×100

=0.096/0.24×100

=60%

% of oxygen = mass of oxygen/mass of the compound×100

=0.144/0.24×100

=40%

Answer 2

Answer:

Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%

Explanation:

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