Chemistry, asked by hiranmoychakraborty6, 11 months ago

A. 0.26 g of a metal hydride contains 0.02 g of hydrogen. What is the equivalent weight ofthe metal ?(A) 28(B) 24(C) 16(D) 12B. Which one is used to treat acid indigestion ?(A) Be(OH)2e(B) KOH(C) Mg(OH)2(D) Ca(OH)2C. The oxidation number of carbon in C12H22O11 is(A) 0 (B) +22(C) +6(D) –6​

Answers

Answered by muksun03
0

A . let M is atomic mass and x is valency of metal , E. then, metal hydride is EHx.

so, molar mass of EHx = (M + x) g/mol

in metal hydride,

one mole of metal hydride contains x moles of hydrogen.

so, (M + x)g of metal hydride contains x g of hydrogen.

or, 0.26g of metal hydride contains x/(M + x) × 0.26 g of hydrogen.

but given mass of hydrogen = 0.02g

or, x/(M + x) × 0.26 = 0.02

or, x/(M + x) = 1/13

or, 13x = M + x

or, 12x = M

or, M/x = 12

hence, equivalent weight = atomic mass/valency = M/x = 12.

B. Mg(OH)2 , milk of magnesia is used to treat acid indigestion.

C. zero, because C12H22O11 is covalent organic compound and we know, covalent bond is formed by sharing of electrons.

Explanation:

pls mark it as brainliest answers

Similar questions