Question

A(0,3) B(K,0) and AB=5 find the positive value of K
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Answer 1

${5}^{2} = {(0 - 3)}^{2} + {(k - 0)}^{2} \\ 25 = 9 + {k}^{2} \\ {k}^{2} = 16 \\ k = \sqrt{16 } \\ k = + 4$