A 0.3- μf capacitor has an initial charge of 2.7 v. if it is discharged through a 10-kω resistor for 6.5 ms, how much voltage will be left across the capacitor?
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Q=CV
V=Q÷C
V=2.7÷0.3×10^_6
V=9×10^6 volt
hope it will help u
if yes Mark as brainlies
V=Q÷C
V=2.7÷0.3×10^_6
V=9×10^6 volt
hope it will help u
if yes Mark as brainlies
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