Physics, asked by darkprince7807131834, 9 months ago



A 0.3 kg mass is attached to a spring and oscillates at 2 Hz with a Q of 60. Find the

spring constant and damping constant.​

Answers

Answered by archanazara
3

Explanation:

क्लास टू गो टू रामेश्वरम रामेश्वरम मुझे पात्र को दी रानी की काल कार्यक्रम में मुझे पता नहीं कि उसका पार्क ग्रीन है धन्यवाद

Answered by archanajhaasl
0

Answer:

The spring constant and damping constant of the string are 47.4N/m and 30 respectively.

Explanation:

The spring constant is given as,

k=m(2\pi f)^2      (1)

Where,

k=spring constant

m=mass of the string

f=frequency of the string

Also,

Damping constant,

\tau=\frac{1}{2} Q            (2)

τ=damping constant

Q=quality factor

From the question we have,

m=0.3kg

f=2Hz

Q=60

By substituting the required values in equation (1) we get;

k=0.3\times (2\pi \times 2)^2

k=47.4N/m       (3)

And by substituting the value of "Q" in equation (2) we get;

\tau=\frac{1}{2} \times 60=30

Hence, the spring constant and damping constant of the string are 47.4N/m and 30 respectively.

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