a 0.30kg apple hangs from a branch. if the apple has 7.35J of gravitational potential energy, what is the height of the apple above the ground
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Given - Mass of apple - 0.30 kilogram
Gravitational potential energy of apple - 7.35 joules
Find - Height of apple above the ground.
Solution - Gravitational potential energy is given by the formula - U = m*g*h. In the formula, U stands for gravitational potential energy, m refers to mass of body, g represents gravitational field and h stands for height.
Keeping the given values in formula to calculate height -
h = U/m*g
Assuming g to be 10 m/s².
h = 7.35/0.30*10
h = 2.45 metres
Hence, the height of apple from ground is 2.45 metres.
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