Physics, asked by iu740393gmailcom, 6 months ago


A 0.340 kg particle moves in an XY plane according
to.x(t) =
= -15.00 + 2.00t - 4.00^3 and y(t) = 25.00 + 7.00t - 9.00t^2
with x and y in meters and t in seconds. At i = 0.700 s. what are (a)
the magnitude and (b) the angle (relative to the positive direction
of the x axis) of the net force on the particle and (c) what is the
angle of the particle's direction of travel?​

Answers

Answered by kavitadhangar2008
1

Answer:

ycyvub

Explanation:

cytcttcuhoxuzydfuggfxfuxg get wgusvj

iwbuzsbb

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