A 0.34g sample of compound of iron sulfide was found by analysis to contain
0.204g of iron and 0.136g of sulphur. Calculate the percentage composition of the
compound by weight.
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When a mixture of iron and sulphur is heated strongly, they first absorb the energy to get excited. This is followed by the formation of a new compound iron sulphide (FeS) with the release of huge amount of energy in the form of heat.... Therefore, heat is liberated out in the reaction...
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Answer:
iron = 60%
sulphur = 40%
Explanation:
Percentage of iron = 0.204/0.34*100 = 60%
percentage of sulphur = 100 - percentage of iron = 40%
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