Physics, asked by Jusjyotimema, 1 year ago

A 0.3H inductor 60micro farad capacitor & a 50ohm resistor are connected in series with a 120V , 60hz supply . Calculate (1) Impedance of the circuit & current flowing in the circuit.

Answers

Answered by kvnmurty
28
Impedance of LCR series circuit :   R  + (j ωL + (iωC)⁻¹ )
               Z =  R + j [ωL - 1/ωC]
   ω=2π*f,  X_L = 2π*60 *0.3=  36π Ohms,  
    R = 50 Ohms,    X_C = 1/(120π*60*10⁻⁶) Ohms

Impedance = | Z |  = √[R² + (X_L - X_C)²] = 85.12 Ohms

current flowing (RMS) = 120V/85.12 ohms = 1.41 Amps

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