A(0,4),b(0,-4) are two points the locus of p which moves such that pa-pb=6
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Given, a(0,4) and b(0,-4)
Let p(x,y) be the point on locus
Given condition, |pa- pb|= 6
pa-pb = +or - 6
pa =pb+or-6
Squaring on both sides
pa^2= pb^2 +36+or - 12pb
x^2 +(y-4)^2= x^2+(y+4)^2+36+or-12pb
After simplification we get,
4y +9=+or- 3pb
Again squaring on both sides,
16y^2+81+36y=9pb^2
16y^2+81+36y=9( x^2+ (y+4)^2)
After simplification finally we will get,
9x^2-7y^2+36y+63=0
Let p(x,y) be the point on locus
Given condition, |pa- pb|= 6
pa-pb = +or - 6
pa =pb+or-6
Squaring on both sides
pa^2= pb^2 +36+or - 12pb
x^2 +(y-4)^2= x^2+(y+4)^2+36+or-12pb
After simplification we get,
4y +9=+or- 3pb
Again squaring on both sides,
16y^2+81+36y=9pb^2
16y^2+81+36y=9( x^2+ (y+4)^2)
After simplification finally we will get,
9x^2-7y^2+36y+63=0
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