A 0.4 kg block with an initial speed of 0.7 m/s slides along a horizontal tabletop against a friction of 0.7 N.How far will it slide before stopping?
Answers
Answer:
- Distance covered by block before stopping = 0.14 m
Explanation:
Given
- Mass of block, m = 0.4 kg
- Initial velocity of block, u = 0.7 m/s
- Final velocity of block, v = 0 [Since, it comes to rest after sliding a certain distance]
- Friction force of tabletop acting on the particle, F = -0.7 N
[Negative F because Friction force would be acting in the opposite direction of motion]
To find
- Distance covered by block before stopping, s =?
Knowledge required
- Work-energy theorem
According to the work-energy theorem the work done is equal to the change in kinetic energy of the particle.
W = Final K.E. - Initial K.E. = 1/2 m v² - 1/2 m u²
- Formula to calculate work
W = F . s
[ Where W is work done, m is mass, v is final velocity, u is initial velocity, F is force and s is the distance covered by the particle ]
Solution:
Since, By work-energy theorem
→ W = 1/2 m v² - 1/2 m u²
and, Also we know,
→ W = F . s
therefore,
→ F . s = 1/2 m v² - 1/2 m u²
→ (-0.7) · s = 1/2 · m · (0)² - 1/2 · (0.4) · (0.7)²
→ -0.7 s = -0.2 · (0.7) · (0.7)
→ - s = -0.2 · (0.7)
→ s = 0.14 m
Therefore,
- Distance covered by block before stopping would be 0.14 metres.
Answer:
Explanation:
Answer:
Distance covered by block before stopping = 0.14 m
Explanation:
Given
Mass of block, m = 0.4 kg
Initial velocity of block, u = 0.7 m/s
Final velocity of block, v = 0 [Since, it comes to rest after sliding a certain distance]
Friction force of tabletop acting on the particle, F = -0.7 N
[Negative F because Friction force would be acting in the opposite direction of motion]
To find
Distance covered by block before stopping, s =?
Knowledge required
Work-energy theorem
According to the work-energy theorem the work done is equal to the change in kinetic energy of the particle.
W = Final K.E. - Initial K.E. = 1/2 m v² - 1/2 m u²
Formula to calculate work
W = F . s
[ Where W is work done, m is mass, v is final velocity, u is initial velocity, F is force and s is the distance covered by the particle ]
Solution:
Since, By work-energy theorem
→ W = 1/2 m v² - 1/2 m u²
and, Also we know,
→ W = F . s
therefore,
→ F . s = 1/2 m v² - 1/2 m u²
→ (-0.7) · s = 1/2 · m · (0)² - 1/2 · (0.4) · (0.7)²
→ -0.7 s = -0.2 · (0.7) · (0.7)
→ - s = -0.2 · (0.7)
→ s = 0.14 m
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