Question

A 0.4 kg block with initial speed of 0.8m/s slides along a horizontal table against a friction force 0f 0.70N. Ho
w far will it slide before stopping?

Answer 1

F=uN=umg

a=ug

F=ma

a=0.7/0.4

a=1.75

U=0.8

V=0 as the block stops after sliding

V²=U²+2aS

U²=2as

0.64/2×1.75=S

S=0.18m

I hope this helps ( ╹▽╹ )