Question

A 0.40 kg soccer ball approaches a player horizontally with a velocity of 18 m/s to the north. The player strikes the ball and causes it to move in the opposite direction with a velocity of 22 m/s. What impulse was delivered to the ball by the player?

Answer 1

Answer:

Explanation:

I hope this helps you

Answer 2

Given:

• Mass of Ball = 0.40 kg
• Initial velocity = 18 m/s towards North
• Final velocity = 22 m/s towards South

To find:

Impulse delivered to ball ?

Calculation:

• Let us consider the vector direction towards South to be positive.

So, let impulse be I , it will be calculated as change in linear momentum of ball:

$\therefore \: I = \Delta P$

$\implies\: I = mv - mu$

$\implies\: I = m(v - u)$

$\implies\: I = 0.4 \{22 - ( - 18) \}$

$\implies\: I = 0.4 \{22 + 18\}$

$\implies\: I = 0.4 \times 40$

$\implies\: I = 16 \: kg \: m/s$

So, impulse delivered is 16 kg m/s