A(0,5)B(6,11),C(10,7) are the vertices of triangle ABC. If D and E are mid points of AB and AC respectively,find the area of triangle ADE
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we can find vertices of point D and E by mid point formula.....
now firstly we find the points of d...
= (X1+X2)/2 AND (Y1+Y2)/2
=(0+6)/2 AND (5+11)/2
=6/2 AND 16/2
=(3,8) are the points of d
now we can find the vertices of point e
=(0+10)/2 and (5+7)/2
=10/2 and 12/2
=(5,6) are the points of e
now area of triangle ADE
=1/2 (X1(Y2-Y3) +X2(Y3-Y1)+X3(Y1-Y2))
=1/2(0(8-6)+3(6-5)+5(5-8))
=1/2(3-15)
=1/2 (-12)
=-6 but area cannot be negative so answer is =6sq.unit
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