A 0.5 kg ball is thrown up into the air with a velocity of 8 m/s. What is the maximum height this ball reaches?
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- A 0.5kg ball is thrown up with a velocity of 8m/s .
- The maximum height attained by the ball.
Given that , a ball is projected vertically upward with initial velocity of 8 m/s . Here when the ball will reach the maximum height then its final velocity will be zero. And the acceleration due to gravity will be -10 m/s² , since the direction of motion of the ball is in opposite direction of acceleration due to gravity . Now using the Third equation of Motion , we have ,
❒ Know More :-
- The maximum height obtained can directly be found out using the Formula , u²/2g , where u is the velocity of projection and g is the acceleration due to the gravity.
- The time of fight equals to 2u/g , where the time of acsent is equal to the time of descent and each equals to u/g .
- Here in the question , mass of the ball was given but velocity doesn't depends on the mass .
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