Question

A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle of 30° with the wall .It is reflected with the same speed and angle If the ball is in contact with the wall for 0.25s ,the average force acting on the wall is
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Answer 1

Answer:

24 N

Explanation:

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Answer 2

Solution :-

Mass of ball = 0.5kg

Initial speed = 12 m/s

Angle with wall = 30°

(Therefore angle with horizontal line will be 60°)

Time of contact = 0.25s

To find : Force acting on the wall.

As per newton's second law of motion force is measured as the rate of change of linear momentum.

So first we have to find linear momentum of ball.

★ Initial momentum :

→ p = mu cos60°

→ p = 0.5 × 12 × 1/2

→ p = 3 N s

Similarly final momentum of ball will be -3 N s. Here negative sign shows opposite direction.

Now, F = dp/dt

→ F = [3 - (-3)]/0.25

→ F = 6/0.25

→ F = 24 N