A 0.5 kg ball travelling at a velocity of 5 m/s strikes vertical wall and rebounds with a velocity of 4 m/s. (a) Find Ap of the object. (b) Determine the impulse of the collision.
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Answer:
2000 N
Step-by-step explanation:
ANSWER
ΔP=MV−(−MV)
2mV
F=tΔP
=ΔP=ft
F=10−3sec2mv
10−32×21×2
=2000N
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