| A 0.5 kg mass is rotated in a horizontal Circle o radius im Calculate the maximum numeber of revolution per minute. so that the string does not ertaking tension of string 15 9.86 N .
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Answer:
94.87 r.p.m.
Explanation:
Mass of body = m = 0.5 kg
Radius = r = 20 cm = 0.2 m
Force = F = 9.86 N
F = mrω²
∴ ω² = F/mr
ω = √9.86/0.5 × 0.2
= 9.93 rad/s
ω = 2πN/60
N = 60ω/2π
= 60×9.93/2×3.14
= 94.87 r.p.m.
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