Question

A 0.5 kg object is released from h height. When it reaches the earth, its momentum becomes 10 Ns. Find the height (g = 10m / sec ^ 2).

Answer 1

h=20 m

Explanation:

mass=0.5kg,momentum(p)=10Ns,g=10m/s^2,h=?

first we find kinetic energy of the object by using K.E=p^2/2m

=100/2*0.5

=100 joule

now in free fall

K.E =mgh

100=0.5*10*h

h=100/5

h=20 m