A 0.5 kg pair of running shoes weigh 11.50 N on Jupiter. How is the force
exerted by the shoes on Earth different from the force exerted on Jupiter?
(g on Earth = 10 m/s2) Please show full working
Answers
Answered by
5
Answer:
The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg:
g=F/m=11.55N/0.5kg=23.1m/s^2
Answered by
3
Given:
Mass, m = 0.5 kg
Weight on Jupiter, Wj = 11.5 N
g (on earth) = 10 m/s²
To Find:
Comparison of force exerted by the shoes on Earth and Jupiter.
Calculation:
- Force exerted by the shoes on the Earth, i.e., the weight of the shoes on the Earth is given as:
We = m × g
⇒ We = 0.5 × 10
⇒ We = 5 N
- Taking the ratio of force exerted by the shoes on the Jupiter and the Earth, we get:
Wj / We = 11.5 / 5
⇒ Wj = 2.3 We
- Hence, the force exerted by the shoes on the Jupiter is 2.3 times the force exerted by them on the Earth.
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