Physics, asked by Anonymous, 9 months ago

A 0.5 kg pair of running shoes weigh 11.50 N on Jupiter. How is the force
exerted by the shoes on Earth different from the force exerted on Jupiter?
(g on Earth = 10 m/s2) Please show full working

Answers

Answered by sheranrana5377
5

Answer:

The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg:

g=F/m=11.55N/0.5kg=23.1m/s^2

Answered by Jasleen0599
3

Given:

Mass, m = 0.5 kg

Weight on Jupiter, Wj = 11.5 N

g (on earth) = 10 m/s²

To Find:

Comparison of force exerted by the shoes on Earth and Jupiter.

Calculation:

- Force exerted by the shoes on the Earth, i.e., the weight of the shoes on the Earth is given as:

We = m × g

⇒ We = 0.5 × 10

⇒ We = 5 N

- Taking the ratio of force exerted by the shoes on the Jupiter and the Earth, we get:

Wj / We = 11.5 / 5

Wj = 2.3 We

- Hence, the force exerted by the shoes on the Jupiter is 2.3 times the force exerted by them on the Earth.

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