Question

A 0.5 m length of current-carrying wire kept perpendicular to a magnetic field of
magnitudie 200 mT experiences a force of 1.5 mN. What is the current flowing in the
wire?
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Answer 1

The length of current carrying wire = l = 0.5 meters

The magnitude of magnetic field = B = 200 ×   Tesla

The Force exerted = F = 1.5 ×    Newton

To Find :

The magnitude of current flowing in the  wire

Solution :

Force exerted on current carrying wire is given as

Force = current × length of wire × magnetic field

i.e  F = i l B

or,  1.5 ×   N  = i × 0.5 m × 200 ×   Tesla

Or,  1.5 ×   N = 100 ×  × i

∴    i =   Amp

i.e  i =  Amp

Or, Current = i = 0.015 Amp

Hence, The magnitude of current flowing in the  wire is 0.015 Amp   Answer