Question

A 0.50 g bullet is fired at 900 m/s in a straight line 1.5 m above the ground. Calculate the total mechanical energy of the bullet.

Answer 1

Answer:

202.5 J

Explanation:

Total mechanical energy = Kinetic Energy + Potential Energy.

Answer 2

the total mechanical energy of the bullet. = 202.50735   Joule if 0.50 g bullet is fired at 900 m/s ,  1.5 m above the ground.

Explanation:

total mechanical energy of the bullet.  = Kinetic Energy + potential Energy

Kinetic energy = (1/2)mv²

Potential energy = mgh

m = 0.5  g  = 0.5 * 10⁻³ kg

v = 900 m/s

g = 9.8 m/s²

h = 1.5  m

Kinetic energy = (1/2)mv²   = (1/2) (0.5* 10⁻³ )(900)² = 2,02.5  joule

Potential Energy =  mgh = (0.5* 10⁻³ ) (9.8) 1.5  = 0.00735 joule

total mechanical energy of the bullet.  = 202.5  + 0.00735 joule = 202.50735  Joule

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