Question

A 0.50-kg object moves in a horizontal circular track with a radius of 2.5 m. An external force of 3.0 N, always tangent to the track, causes the object to speed up as it goes around. What is the work done by the external force as the mass makes one revolution?

Answer 1

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Explanation:

“Always tangent to the track” means the angle between the force and the displacement is 0 degrees

1 rev = 2 x 2.5 x pi = 15.708 m

3 x 15.708 = 47.12 J

Answer 2

Answer:

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