A 0.561 m solution of unknown electrolytic depresses the freezing point of water by 2.93 C. What is Bob't Hoff factor for this electrolyte. The freezing point depression f oh r water is 1.86 C kg/mol
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Answer:
Explanation:
firstly its van't hoff factor(i)
ΔT=iK(f)m
i=ΔT/K(f)m
i=2.93/(1.86*0.561)
i=2.8
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