Chemistry, asked by shakirainapure2838, 9 months ago

A 0.561 m solution of unknown electrolytic depresses the freezing point of water by 2.93 C. What is Bob't Hoff factor for this electrolyte. The freezing point depression f oh r water is 1.86 C kg/mol

Answers

Answered by rohitchak21pam42i
2

Answer:

Explanation:

firstly its van't hoff factor(i)

ΔT=iK(f)m

i=ΔT/K(f)m

i=2.93/(1.86*0.561)

i=2.8

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