Question

a 0.5kg ball is thrown up with a velocity of 20m/sec. Find the work done done by the ball in 2 sec.​

Answer 1

Answer:

Kinetic energy = 1 2 * m * v^2

Potential energy = mgh

Where m = mass of ball = 0.5 kg

g = acceleration due to gravity = 9.8 m sec^2

v = velocity of ball = 20 m/s

h = maximum height

Hence kinetic energy = 1/2 * 0.5 * 20 * 20 = 100 joules

Now potential energy = 0.5 * 9.8 * h = 100

Maximum height = 100/4.9 = 20.4 m

Explanation:

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