A 0.5kg ball moving with speed of 12m/s strikes a hard wall at an angle 30 with the wall. It is reflected with same speed and at the same angle if the ball is in contact with the wall for 0.25s,the average force acting on the wall is?
Answers
Answered by
159
F (average) = m (vf - vi)/t
Vf =0 m/s
Vi =12 m/s
Therefore by the formula,
Favg. = m (vf - vi)/t
= 0.5 (12)/0.25
= 24 N
Vf =0 m/s
Vi =12 m/s
Therefore by the formula,
Favg. = m (vf - vi)/t
= 0.5 (12)/0.25
= 24 N
Answered by
50
F (average) = m (vf - vi)/t
Vf =0 m/s
Vi =12 m/s
Therefore by the formula,
Favg. = m (vf - vi)/t
= 0.5 (12)/0.25
= 24 N
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