Question

A 0.6 kg ball is attached to a light string rotates in a vertical circle of radius 0.75 m such that its speed is 5m/s ,when the string is horizontal temsion in string is ?

Answer 1

Hey mate..

Here is your answer..

Tension = Force + mg

$= mr {w}^{2} + mg \\ = 0.6 \times 0.75 \times (5 \div 0.75) + 0.6 \times 10 \\ = 8.9 = 9 \: newton$

HOPE that it will help you ✌️ ✌️