A 0.674 M cobalt(ii) chloride (CoCl2) solution is prepared with a total volume of 0.0750 L. The molecular weight of CoCl2 is 128.9 g/mol.
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Answer:
Explanation:
Molarity = given mass / molar mass * volume (l)
so applying it in the formula
0.674 = x / 128.9 * 0.0750
x= 1158.2 g is the required mass to be dissolved to make 0.674 M soln
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