Chemistry, asked by morenomaritza1029, 11 months ago

A 0.674 M cobalt(ii) chloride (CoCl2) solution is prepared with a total volume of 0.0750 L. The molecular weight of CoCl2 is 128.9 g/mol.

Answers

Answered by vaishnav0070
0

Answer:

Explanation:

Molarity =  given mass / molar mass * volume (l)

so applying it in the formula

0.674 = x / 128.9 * 0.0750

x= 1158.2 g is the required mass to be dissolved to make 0.674 M soln

Similar questions