Question

a=0,b=2,c=3 8(2a+b)-[12b-{7a-(3b-a)}]​

Answer 1

• As per the data given in the question, we have to find the value of the expression.

            Given data:- $a=0,b=2,c=3.$

            To find:- $8(2a+b)+[12b-(7a-(3b-a))]=?$

            Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:

• Step 1:- we will Identify the variables and constants in the given simple equation.

• Step2:-then we Simplify the equation in  LHS and RHS.

• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.

• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5:- Then the result will be the solution for the given linear equation. By using the transposition method. we get,

            $8(2a+b)+[12b-(7a-(3b-a))]\\=8(2(0)+2)+(12(2)-(7(0)-(3(2)-0)))\\=16+(24-0-6-0)\\=16+18\\=34.$

         Hence we will get the value $34.$