a 1.0 CM high object is placed at a distance of 12 CM from a convex lens of focal length 16 CM find the position of the image and is the image is real or virtual also find the size of the image and is the image erect or inverted
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Explanation:
for (a) position of the image with the given values like u= -12 , f=16 solve and get the positions where you need to use this formulae 1/f=1/v-1/u where your answer will be v=60cm
(b) m=v/u
=-60/12
=-5
Since magnification is negative the image is real.
(c) The size of the image is smaller than that of object.
(d) The image is inverted
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