Question

A 1.0 hp motor pumps out water from a well of depth 20m and fills a water tank of volume 2238 liters at a height of 10m from the ground . The running time of the motor to fill the empty water tank is (g=10)

Answer 1

Mass of water from well => density x volume => 1*2238 gms or 2.238 Kg.
Work = mgh => 2.238*10*20 => 447.6 J
For height 10 m from the ground= > 2.238*10*10 => 223.8 J
Net Energy required = > 447.6 – 223.8 => 223.8 J
1 HP =746 w = 746 J
time required => 223.8/746 => 0.3 seconds

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Answer 2

Mass of water from well => density x volume => 1*2238 gms or 2.238 Kg.

Work  = mgh => 2.238*10*20 => 447.6 J For height 10 m from the ground= >  2.238*10*10 => 223.8 J

Net Energy required = > 447.6 – 223.8 => 223.8 J


1 HP =746 w = 746 J

time required => 223.8/746 => 0.3 seconds.