Question

A 1.0-kg ball moving at 2.0 m/s perpendicular to a wall rebounds from the wall at 1.5 m/s. The change in the momentum of the ball is

Answer 1

Explanation:

Given A 1.0-kg ball moving at 2.0 m/s perpendicular to a wall rebounds from the wall at 1.5 m/s. The change in the momentum of the ball is

• The given ball has a mass of 1 kg.
• So the speed of the ball before hitting the wall (collision) was 2 m/s
• Speed of the ball after collision is 1.5 m/s
• Now change in momentum is  
•                                              Δm = mf – mi (mf and mi are momentum after and before striking the wall)
• Now direction of ball before striking will be positive and in negative direction after it rebounds striking the wall.
• Change in momentum will be
•                                               mod Δm = mod – mvf – mvi
•                                                                        = 1 x 1.5m/s + 1 x 2 m/s
•                                                                            = 1 (1.5 + 2)
•                                                                             = 3.5 kg m/s

Reference link will be

https://brainly.in/question/38783048