Physics, asked by kavinkrishna24, 6 months ago

A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up
to a maximum height, then returns to the ground. Calculate the rock’s momentum as it strikes the
ground.

Answers

Answered by xxZUBAKOxx
8

Explanation:

The Initial velocity of Rock=8.00 m/s

Let g= 10 (approx)

Time taken to travel at maximum height = 8/10 = .8 second

At max height Initial velocity be = 0

Then Final velocity at .8 second= 10 × .8 = 8

P = MV = 1×8 =. 8kgm/s.......

Answered by GulabLachman
6

Given: A 1kg rock is thrown up into the air from ground level at a speed of 8 m/s. The ball travels up to a maximum height then returns to the ground.

To find: The rock's momentum as it strikes the ground

Explanation: At highest point the velocity of the ball is zero.

Final velocity= Initial velocity - g * time

=> 0 = 8 - 10 t

=> t = 8/10

= 4/5

At the highest point the initial velocity of the ball is zero.

Using kinematics formula,

Final velocity= Initial velocity+ g*time

= 0+ 10* 4/5

= 8 m/s

Momentum as it strikes the ground= Mass* Final velocity

=> Momentum= 1 * 8

= 8 kg m/s

Therefore, the rock's momentum as it strikes the ground is 8 kg m/s.

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