A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up
to a maximum height, then returns to the ground. Calculate the rock’s momentum as it strikes the
ground.
Answers
Explanation:
The Initial velocity of Rock=8.00 m/s
Let g= 10 (approx)
Time taken to travel at maximum height = 8/10 = .8 second
At max height Initial velocity be = 0
Then Final velocity at .8 second= 10 × .8 = 8
P = MV = 1×8 =. 8kgm/s.......
Given: A 1kg rock is thrown up into the air from ground level at a speed of 8 m/s. The ball travels up to a maximum height then returns to the ground.
To find: The rock's momentum as it strikes the ground
Explanation: At highest point the velocity of the ball is zero.
Final velocity= Initial velocity - g * time
=> 0 = 8 - 10 t
=> t = 8/10
= 4/5
At the highest point the initial velocity of the ball is zero.
Using kinematics formula,
Final velocity= Initial velocity+ g*time
= 0+ 10* 4/5
= 8 m/s
Momentum as it strikes the ground= Mass* Final velocity
=> Momentum= 1 * 8
= 8 kg m/s
Therefore, the rock's momentum as it strikes the ground is 8 kg m/s.