Question

a 1.0kw kettle contains 500g boiling water. calculate the time needed to evaporate all the water in the kettle(specifice latent heat of vaporization of water = 2.26Mj/kg)​

Answer 1

Answer:

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Answer 2

Given:

mass of water = 500 g

Power = 1 KW

specific latent heat of vaporization of water = 2.26Mj/kg

To find:

time t =?

Step-to-step-explanation:

• We have to find the time needed to evaporate all the water in the kettle.
• The boiling point of water is 100°C.
• Hence we have to find the time needed to boil water up to 100°C.
• First, the heat required to boil water up to 100°C is given by:

        Heat = mass × specific latent heat × temperature

                 = 500 × 2.26 × 100

                 = 113000 J

• The power required to boil the cattle is 1 KW i.e. 1000 W.
• We know that power is the ratio of energy & time.

        $\displaystyle P=\frac{H}{t}$

        $\displaystyle 1000 = \frac{113000}{t}$

         t =  113 sec

         t = 3 min 23 sec

• Hence, the time needed to evaporate all the water in the kettle is 3 min 23 sec.