Physics, asked by meghakatiyar1, 1 year ago

A 1.1 KW heater is connected to 220V mains . calculate ===

a) current flowing through the heater .

b) resistance if the heater

c) electrical energy consumed in KW. if the heater is used on an average for 1 H daily in a month of 30 days .

Answers

Answered by AryanTennyson
14
Aryan.........PVT.....LTD.......
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Answered by sarithavalsanpdumbq
94

Given Data :

Power = 1.1 KW = 1.1 * 1000 W = 1100 W

Voltage = 220 Volts

A) We know that,

P = VI

1100 = 220*I

I = 5 Amperes


B) We also know that,

P = V2 / R

1100 = 220*220/R

R = 44 ohms


C) Here, P = 1.1 KW

Time per day is 1 hour

Then time for 30 days is 30 hours

The formula for commercial unit of energy is KwH

Then energy consumed by the heater in 30 days is 1.1 Kw * 30 H

Energy = 33 KwH

Hope this will help you give be 5 stars

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