Question

a) {-1/2+1/3+1/6 } *(-2/5)
answer will be 0 but find out how the answer will be 0



please answer it fast and don't send rubbish answer

and answer it with process and send a pic or write the full answer and explain that how you did this

if u will give rubbish answer then it will be reported with 5 more answers

and try to answer my previous questions​

Answer 1

Answer:

Using appropriate properties, find:

(i) -2/3 * 3/5 + 5/2 – 3/5 * 1/6 (ii) 2/5 * (3/-7) – 1/6 * 3/2 + 1/14 * 2/5

Answer:

(i) -2/3 * 3/5 + 5/2 – 3/5 * 1/6

= -2/3 * 3/5 – 3/5 * 1/6 + 5/2 [Using associative property]

= 3/5 * (-2/3 – 1/6) + 5/2 [Using distributive property]

= 3/5 * {(-4 - 1)/6} + 5/2 [LCM (3, 2) = 6]

= 3/5 * (-5/6) + 5/2

= -3/6 + 5/2

= -1/2 + 5/2

= (-1 + 5)/2

= 4/2

= 2

Step-by-step explanation:

this is the similar answer use this method for your answer

Answer 2

$\: \: \: \sf : \implies \: \bigg( \dfrac{ - 1}{2} + \dfrac{1}{3} + \dfrac{1}{6} \bigg) \times \bigg( \dfrac{ - 2}{5} \bigg)$

Solving the first bracket :

$\: \: \: \sf : \implies \: \bigg( \dfrac{ - 1}{2} + \dfrac{1}{3} + \dfrac{1}{6} \bigg)$

LCM of 2, 3 and 6 is 6 :

$\: \: \: \sf : \implies \: \dfrac{ - 1}{2} \times \dfrac{3}{3} = \dfrac{ - 3}{6} \: \: \: \red{|} \: \: \: \dfrac{1}{3} \times \dfrac{2}{2} = \dfrac{2}{6} \: \: \: \red{ | } \: \: \: \dfrac{1}{6} \times \dfrac{1}{1} = \dfrac{1}{6}$

Adding them up :

$\: \: \: \sf : \implies \: \bigg( \dfrac{ - 3 + 2 + 1}{6} \bigg) \times \bigg( \dfrac{ - 2}{5} \bigg)$

$\: \: \: \sf : \implies \: \bigg( \dfrac{ - 3 + 3}{6} \bigg) \times \bigg( \dfrac{ - 2}{5} \bigg)$

$\: \: \: \sf : \implies \: \bigg( \dfrac{0}{6} \bigg) \times \bigg( \dfrac{ - 2}{5} \bigg)$

We know that anything divided by 0 is 0 :

$\: \: \: \sf : \implies \: (0) \times \bigg( \dfrac{ - 2}{5} \bigg)$

Also, we know that anything multiplied to 0 gives 0 :

$\: \: \: \sf : \implies \: 0$

So, the final answer is :

$\boxed {\therefore \: \bf{ The \: value \: of \: \bigg( \dfrac{ - 1}{2} + \dfrac{1}{3} + \dfrac{1}{6} \bigg) \times \bigg( \dfrac{ - 2}{5} \bigg) \: is \: 0 . }}$