Question

A=[1 2/1 3] b= [4 0/ 1 5] c=[ 2 0/1 2] find (a-b) c=ac-bc

Answer 1

Answer:

(a-b)c=ac-bc

(12/13 - 40/15)*20/12 = 12/13*20/12 - 40/15*20/12

(180-520)/195*20/12 = 20/13 - 8/3*5/3

-340/195*5/3 = 20/13 - 40/9

-340/39*1/3 = (180-520)/117

-340/117 = -340/117

therefore, LHS=RHS