A = { 1, 2, 3, 4, 5), B = { 2, 3, 6, 7, 8). Find n(AUB), n(AB) and verify the result
using n(A) + n(B) - n(ANB) = n(AUB).
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hell......ooooo
1 . n (AuB) =
A = 1,2,3,4,5
B = 2,3,6,7,8
AuB = 1,2,3,4,5,6,7,8
n = 8
n(AuB)=8
2.A = 1,2,3,4,5
B = 2,3,6,7,8
n(A) = 5
n(B)= 5
3.A = 1,2,3,4,5
B = 2,3,6,7,8
( AnB ) = 2,3
n(AnB ) = 2
formula...
n(A) + n(B) - n(ANB) = n(AUB).
5 + 5 - 2 = 8
10 - 2 = 8
8 = 8
hence it solved....
hey mate dont confuse
n means total....
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