A={1,2,3,4} and B={3,4,5,6} Find A∆B
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Answered by
3
Answer:
{1,2,5}
Step-by-step explanation:
A∆B which is called the symmetric difference between A and B is defined as (A-B)U(B-A).
Now, A-B is the set of all elements which are in A but not in B. So, A - B = {1,2}.
Similarly, B-A is the set of all elements which are in B but not in A. So, B - A = {5}.
Hence A ∆ B = (A-B)U(B-A) = {1,2,5}
Answered by
6
Step-by-step explanation:
(A-B) U (B-A)
=[{1,2,3,4}-{3,4,5,6}]U[{3,4,5,6}-{1,2,3,4}]
={1,2}U{5,6}
={1,2,5,6}
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