A = {1,2,3,4}; B = {2,3,5, then ΑΔΒ = 2,4} and A {1,4,5,3} = {x/x is a B {1,3,4,5) CLA C {1,4,5,7) figure is b) {2,3 d) {1, S. D {2,3,1,5}
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Correct option is
D
{1,5,6}
AΔB=(A∪B)−(A∩B)
={1,2,3,4,5,6,}−{2,3,4}
={1,5,6}
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