A={1,2,5,7,9}, Q={2,3,5,9,11}, R={3,4,5,7,9} and S={2,3,4,5,8}, then find
(P'U'Q ‘U’ R
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Answer:
in this case the "P" is "A"
(PU Q) = {1, 2, 5, 7, 9}U {2, 3, 5, 9, 11} ⇒ (PU Q) = {1, 2, 3, 5, 7, 9, 11} Now, (PU Q)U R = {1, 2, 3, 5, 7, 9, 11}
U {3, 4, 5, 7, 9}
→ (PU Q)U R= = {1, 2, 3, 4, 5, 7, 9, 11}
Hence, (PU Q) U R =
=
{1, 2, 3, 4, 5, 7, 9, 11}.
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