Question

A={1,2,5,7,9}, Q={2,3,5,9,11}, R={3,4,5,7,9} and S={2,3,4,5,8}, then find ; R ii). (QS)R​

Answer 1

Solution :-

→ Q = {2, 3, 5, 9, 11}

→ S = {2, 3, 4, 5, 8},

so,

→ (Q ∩ S) = Set contains elements common in both set Q and set S = {2, 3, 5, 9, 11} ∩ {2, 3, 4, 5, 8} = {2, 3, 5}

now,

→ (Q ∩ S) = {2, 3, 5}

→ R = {3, 4, 5, 7, 9}

then,

→ (Q ∩ S) ∩ R = {2, 3, 5} ∩ {3, 4, 5, 7, 9} = {3, 5} (Ans.)

Learn more :-

A={2,5,7,8,9,} and B={7,8,10,11} then A ∆ B

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