Math, asked by ripalpatel22, 10 months ago

(a+1)²+(a-1)²-(a+1)(a-1)​

Answers

Answered by ketubh
1

Step-by-step explanation:

(a + 1) {}^{2}  - (a + 1)(a - 1) + (a - 1) {}^{2}

(a + 1)(a + 1 -1) + (a - 1)(1 + a - 1)

a \times (a + 1) + a  \times (a - 1)

a(a + 1 + a - 1)

2a \times a = 2a {}^{2}

Answer is above

Answered by adityaprabhakar2004
1

The answer is

 {a}^{2}  + 3

Step-by-step explanation:

 {(a + 1)}^{2}  +  {(a  -  1)}^{2}  - (a - 1)(a + 1)

Opening brackets using (a+b)^2, (a-b)^2 and (a-b)(a+b)

 {a}^{2}  + 1 + 2a  +  {a}^{2}  + 1 - 2a -  ({a}^{2}  - 1)

 {a}^{2}  + 1 + 2a +  {a}^{2}  + 1 - 2a -  {a}^{2}  + 1

Clearly, 2a will be cancelled out

2 {a}^{2}  -  {a}^{2}  + 3

 {a}^{2}  + 3

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