A(1,2) and B(2,3) are given points. Find the point C ∈ AB such that C-A-B and 2AC = 3AB.
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Step-by-step explanation:
3AC=CB
or, AC/CB=1/3
If we denote the coordinate of C by (x,y) then
x=(mx₂+nx₁)/(m+n)
y=(my₂+ny₁)/(m+n)
Here, (x₁,y₁)=(1,1), (x₂,y₂)=(2,-3) and m:n=1:3
∴, x=(1×2+3×1)/(1+3)
=(2+3)/4
=5/4
y=(1×-3+3×1)/(1+3)
=(-3+3)/4
=0
∴, coordinate of C is (5/4,0) Ans.
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