Math, asked by shaahank6664, 8 months ago

a^1/2 +b^1/2 -c^1/2 =0. Then find
(a+b-c)^2

Answers

Answered by mhanifa
2

Answer:

4ab

Step-by-step explanation:

a^1/2 +b^1/2 -c^1/2 =0

Then find  (a+b-c)^2

===========

a^1/2 +b^1/2 -c^1/2 =0

⇒ a^1/2 +b^1/2= c^1/2

⇒ (a^1/2 +b^1/2)^2= (c^1/2)^2

⇒ a+b+2a^1/2*b^1/2= c

⇒ a+b-c=2a^1/2*b^1/2

⇒ (a+b-c)^2=(2a^1/2*b^1/2)^2

⇒ (a+b-c)^2=4ab

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