a(1,2) b(3,6) c(-2,1) are the vertices of the triangle abc find the equation of the perpendicular bisector of line segment bc
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Step-by-step explanation:
Let A(3,4),B(−1,2) be given points CD be required perpendicular bisector.
C is the mid point of AB
Coordinate of C=(23−1,24+2)=(1,3)
Slope of AB=x2−x1y2−y1
=−1−32−4
=−4−2=21
CD⊥AB
Slope of CD=−2
The equation of CD is
y−y1=m(x−x1)
⇒y−3=−2(x−1)
⇒y−3=−2x+2
⇒2x+y−3−2=0
⇒2x+y−5=0
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