A(1,2),B(6,4)C(8,9) are the vertices of the parallelogram ABCD.find the coordinate of D.
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let ABCD be the parallelogram
since the diagonal of parallelogram bisect each other
let the coordinates of D be (x,y)
therefore midpoint of AC=Midpoint of BD
(1+8/2,2+9/2)=(6+x/2,4+y/2)
on comparing;
x=3
y=7
D (x,y)=(3,7)
since the diagonal of parallelogram bisect each other
let the coordinates of D be (x,y)
therefore midpoint of AC=Midpoint of BD
(1+8/2,2+9/2)=(6+x/2,4+y/2)
on comparing;
x=3
y=7
D (x,y)=(3,7)
ijabmrahman:
how this step cam (1+8/2,2+9/2)=(6+x,4+y/2)
Hi
tum messages me aao
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if don't mind sis
this step comes by midpoint formula
mark this answer as brainliest
I no
plz mark this answer as brainliest
thnx sis
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